近似式を立てて探索
#cyber_apocalypse_ctf_2021 from Crypto.Util.number import bytes_to_long from secrets import FLAG,p,q N = p**3 * q e = 0x10001 c = pow(bytes_to_long(FLAG),e,N) print(f'Flag: {hex(c)}') # Hint w = 25965460884749769384351428855708318685345170…
